Help: bash script and "showFolder" binary

[amin]

I wanna use "showFolder" and specify the patch and store it to an string...
all I have is this working script:

#!/bin/bash
. /home/native/.profile
myfile=`basename $0`
mypath=`echo $0 | sed -e 's/'$myfile'//g'`
SelectedFolder=`${mypath}showFolder | sed -n 's/#curfolder#://gp'`
if [ "$SelectedFolder" = "" ]
then
echo "Error"
else
echo "CurrFolder: "${SelectedFolder}
fi

How should I modify that script?

[gorgoyle]

if u want to take arguments from command line check this out:

#!/bin/sh
CalledByName=$0
Arg1=$1;
Arg2=$2;
Arg3=$3;
...
Arg9=$9;
#ARG10=$10 ## that's don't work!

How to use more that 9 Arguments? No Problem!

Arg1=$1; shift;
Arg2=$1; shift;
Arg3=$1; shift;
...
Arg10=$1; shift;
...

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[keaglez]

I think use curly brackets like ${10} will work too...

[gorgoyle]

I didn't test it!

#!/bin/bash
. /home/native/.profile
#one should do the right:
#mypath=${0%/*}
#mypath=${0#/*}
SelectedFolder=$(${mypath}/showFolder | sed -n 's/#curfolder#://gp')
[ $SelectedFolder ] && echo "CurrFolder: ${SelectedFolder}" || echo "Error"

Don't know if it's work but it looks less wired